java使用Hashtable过滤数组中重复值的方法

package org.eline.core.web.support;import java.util.Hashtable;/***************************** * * @author zdw * */public class ObjectFilter{ public static void main(String[] args) {  // String 测试  String arr[] =  { "13111", "13112", "13111" };  ObjectFilter sf = new ObjectFilter();  Object results[] = sf.filter(arr);  System.out.println(results.length);  for (int i = 0; i < results.length; ++i)  {   System.out.println(results[i]);  }  // 整形测试  Integer arr2[] =  { 1, 3, 5, 7, 1, 2, 4, 5 };  Object results2[] = sf.filter(arr2);  for (int i = 0; i < results2.length; ++i)  {   System.out.println(results2[i]);  } } /*************************  * 过滤的方法  *  * @param arr  *   要过滤的数组  * @return  */ public Object[] filter(Object arr[]) {  Hashtable<Object, Object> hashtable = new Hashtable<Object, Object>();  for (int i = 0; i < arr.length; ++i)  {   hashtable.put(arr[i], arr[i]);  }  Object results[] = null;  results = hashtable.values().toArray();  return results; }}