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jquery实现ajax提交form表单的方法总结

2024-05-06 14:28:55
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来源:转载
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方法一:
代码如下:
function AddHandlingFeeToRefund()

        {
            var AjaxURL= "../OrderManagement/AjaxModifyOrderService.aspx";      
            alert($('#formAddHandlingFee').serialize());
                $.ajax({
                    type: "POST",
                    dataType: "html",
                    url: AjaxURL + '?Action=' + 'SubmitHandlingFee' + '&OrderNumber=' + $.trim($("#<%=this.txtOrderNumber.ClientID %>").val()),
                    data: $('#formAddHandlingFee').serialize(),
                    success: function (result) {
                        var strresult=result;
                        alert(strresult);
                        //加载最大可退金额
                        $("#spanMaxAmount").html(strresult);
                    },
                    error: function(data) {
                        alert("error:"+data.responseText);
                     }

                });

        }

方法二:
代码如下:
        //ajax提交form表单的方式
        $('#formAddHandlingFee').submit(function() {
            var AjaxURL= "../OrderManagement/AjaxModifyOrderService.aspx";      

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