JavaScript代码判断输入的字符串是否含有特殊字符和表情代码实例

reg = /[~#^$@%&!?%*]/gi;if (reg.test(postdata.Name.trim())) {alert("姓名不能含有特殊字符");} else {if (isEmojiCharacter(postdata.Name.trim())) {alert("姓名不能含有表情");} else {//自己的代码}}function isEmojiCharacter(substring) {for (var i = 0; i < substring.length; i++) {var hs = substring.charCodeAt(i);if (0xd800 <= hs && hs <= 0xdbff) {if (substring.length > 1) {var ls = substring.charCodeAt(i + 1);var uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;if (0x1d000 <= uc && uc <= 0x1f77f) {return true;}}} else if (substring.length > 1) {var ls = substring.charCodeAt(i + 1);if (ls == 0x20e3) {return true;}} else {if (0x2100 <= hs && hs <= 0x27ff) {return true;} else if (0x2B05 <= hs && hs <= 0x2b07) {return true;} else if (0x2934 <= hs && hs <= 0x2935) {return true;} else if (0x3297 <= hs && hs <= 0x3299) {return true;} else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030|| hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b|| hs == 0x2b50) {return true;}}}}