JavaScript实现构造json数组的方法分析

2024-05-06 16:45:46

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本文实例讲述了JavaScript实现构造json数组的方法。分享给大家供大家参考，具体如下：

从后端拿到的数据是一个数组，每个元素中包含的数据如下(host相同的记录都是相邻的)

currentTime:"1470729601"
host:"10.3.34.21"
taskList:null
taskNum:1

想构造类似如下结构的json数组

[{  name: 'host:10.1.6.49',  data: [    [1470641461000, 5],    [1470642581000, 4],    [1470643701000, 2],    [1470647341000, 3]  ]}, {  name: 'host:10.3.34.18',  data: [    [1470641461000, 2],    [1470642581000, 2],    [1470643701000, 1],    [1470647341000, 4]  ]}, {  name: 'host:10.2.2.22',  data: [    [1470641461000, 3],    [1470642581000, 2],    [1470643701000, 6],    [1470647341000, 4]  ]},{  name: 'host:10.1.110.96',  data: [    [1470641461000, 1],    [1470642581000, 8],    [1470643701000, 1],    [1470647341000, 1]  ]},{  name: 'host:10.2.2.87',  data: [    [1470641461000, 7],    [1470642581000, 3],    [1470643701000, 6],    [1470647341000, 5]  ]}]

错误的方式：

var backendData = data.result;var resultList = new Array();var curHost = "";var oneHostDataList = new Array();for (var i in backendData) {  var host = backendData[i].host;  if (host != curHost) {    if(i != 0) {      var item = new Object();      item.name = curHost;      item.data = oneHostDataList;      resultList.push(item);    }    oneHostDataList = new Array();    curHost = host;  }  else {    var dot = new Array();    dot.push(backendData[i].currentTime * 1000);    dot.push(backendData[i].taskNum);    oneHostDataList.push(dot);  }}var item = new Object();item.name = curHost;item.data = oneHostDataList;resultList.push(item);$scope.data = JSON.stringify(resultList);

以上方式的问题在于转换后会使得name和host和带上引号，正确的方式如下：

var backendData = data.result;var resultList = [];var curHost = "";var oneHostDataList = new Array();for (var i in backendData) {  var host = backendData[i].host;  if (host != curHost) {    if(i != 0) {      var item = {        name: curHost,        data: oneHostDataList      };      resultList.push(item);    }    oneHostDataList = new Array();    curHost = host;  }  else {    var dot = new Array();    dot.push(backendData[i].currentTime * 1000);    dot.push(backendData[i].taskNum);    oneHostDataList.push(dot);  }}var item = new Object();item.name = curHost;item.data = oneHostDataList;resultList.push(item);$scope.data = resultList;

希望本文所述对大家JavaScript程序设计有所帮助。

注：相关教程知识阅读请移步到JavaScript/Ajax教程频道。

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