本文实例讲述了JS实现的字符串数组去重功能。分享给大家供大家参考，具体如下：
这里只考虑最简单字符串的数组去重，暂不考虑，对象，函数，NaN等情况，这种用正则实现起来就吃力不讨好了。
非正则实现：ES6实现
<script>let str_arr=["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"]function unique(arr){ return [...new Set(arr)]}console.log(unique(str_arr)) </script> 运行结果：
ES5实现
<script>var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"] function unique(arr) { return arr.filter(function(ele, index, array) { return array.indexOf(ele) === index }) } console.log(unique(str_arr))</script> 运行结果同上
ES3实现
<script>var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"]function unique(arr) { var obj = {}, array = [] for (var i = 0, len = arr.length; i < len; i++) { var key = arr[i] + typeof arr[i] if (!obj[key]) { obj[key] = true array.push(arr[i]) } } return array}console.log(unique(str_arr))</script> 运行结果同上
用正则实现
<script> var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"] function unique(arr) { return arr.sort().join(",,"). replace(/(,|^)([^,]+)(,,/2)+(,|$)/g, "$1$2$4"). replace(/,,+/g, ","). replace(/,$/, ""). split(",") } console.log(unique(str_arr))</script>
希望本文所述对大家JavaScript程序设计有所帮助。
注：相关教程知识阅读请移步到JavaScript/Ajax教程频道。
