杭电 2029 Palindromes _easy version 回文串

4levelabcdenoonhahaSample Output
yesnoyesno
#include <iostream>#include <string>using namespace std;int main(){	int n;	cin>>n;	while(n--)	{		string str;		cin>>str;		int m=0;		int len=str.length();		for(int i=0;i<len;i++)		{			if(str[i]!=str[len-1-i])			{				break;			}			else				m++;		}		if(m==len)		{			cout<<"yes"<<endl;		}		else			cout<<"no"<<endl;	}	return 0;}