John got a full mark on PAT. He was so happy that he decided to hold a raffle(抽奖) for his followers on Weibo -- that is, he would select winners from every N followers who forwarded his post, and give away gifts. Now you are supposed to help him generate the list of winners.
Input Specification:
Each input file contains one test case. For each case, the first line gives three positive integers M (<= 1000), N and S, being the total number of forwards, the skip number of winners, and the index of the first winner (the indices start from 1). Then M lines follow, each gives the nickname (a nonempty string of no more than 20 characters, with no white space or return) of a follower who has forwarded John's post.
Note: it is possible that someone would forward more than once, but no one can win more than once. Hence if the current candidate of a winner has won before, we must skip him/her and consider the next one.
Output Specification:
For each case, PRint the list of winners in the same order as in the input, each nickname occupies a line. If there is no winner yet, print "Keep going..." instead.
Sample Input 1:9 3 2Imgonnawin!PickMePickMeMeMeeeLookHereImgonnawin!TryAgainAgainTryAgainAgainImgonnawin!TryAgainAgainSample Output 1:PickMeImgonnawin!TryAgainAgainSample Input 2:2 3 5Imgonnawin!PickMeSample Output 2:Keep going...#include<iostream>#include<map>#include<vector>#include<string>using namespace std;int M, N, S;map<string, bool> msb;vector<string> vs;int main(){ scanf("%d%d%d", &M, &N, &S); vs.push_back(" "); string s; for (int i = 0; i < M; i++) { cin >> s; vs.push_back(s); msb[s] = false; } int i = S; if (vs.size() - 1 < S) { cout << "Keep going..." << endl; return 0; } while (i <= M) { if (msb[vs[i]] == false) { cout << vs[i] << endl; msb[vs[i]] = true; i += N; } else { i++; } } return 0;}
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