Find the nth digit of the infinite integer sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, …
Note: n is positive and will fit within the range of a 32-bit signed integer (n < 231).
Example 1:
Input: 3
Output: 3 Example 2:
Input: 11
Output: 0
Explanation: The 11th digit of the sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, … is a 0, which is part of the number 10.
public class Solution { public int findNthDigit(int n) { int len = 1; int start = 1; long cnt = 9; while (n > len * cnt) { n -= len * cnt; len++; cnt *= 10; start *= 10; } start += (n-1) / len; String s = Integer.toString(start); return Character.getNumericValue(s.charAt((n-1) % len)); }}新闻热点
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