Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.For example, given array S = {-1 2 1 -4}, and target = 1. The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).class Solution {
public: int threeSumClosest(vector<int> &num, int t) { int result = 0; int remainder = INT_MAX ; sort(num.begin(), num.end()); for(int i = 0; i < num.size(); i++) twoSum(num, i, result, remainder, t); return result; } void twoSum(vector<int> num, int targetIndex, int& result, int &remainder, int t){ int i = targetIndex + 1; int j = num.size() - 1; while(i < j){ int thisRemainder = num[targetIndex] + num[i] + num[j] - t; if(abs(thisRemainder) <= remainder) { remainder = abs(thisRemainder); result = num[targetIndex] + num[i] + num[j]; } if(thisRemainder > 0) j--; else i++; } } };
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