首页 > 学院 > 开发设计 > 正文

1090.Highest Price in Supply Chain (25)

2019-11-06 07:53:37
字体:
来源:转载
供稿:网友

1090.Highest PRice in Supply Chain (25)

pat-al-1090

2017-03-03

dfs和bfs应该都可以实现,这次尝试了dfs/** * pat-al-1090 * 2017-03-03 * Cpp version * Author: fengLian_s */#include<stdio.h>#include<vector>#define MAX 100010using namespace std;vector<int> v[MAX];int maxDepth = -1, cnt;void dfs(int root, int depth){ if(depth > maxDepth) { maxDepth = depth; cnt = 1; } else if(depth == maxDepth) cnt++; for(int i = 0;i < v[root].size();i++) { dfs(v[root][i], depth+1); }}int main(){ freopen("in.txt", "r", stdin); int n; double p, r; scanf("%d%lf%lf", &n, &p, &r); int root; for(int i = 0;i < n;i++) { int father; scanf("%d", &father); if(father != -1) v[father].push_back(i); else root = i; } dfs(root, 0); for(int i = 0;i < maxDepth;i++) { p *= (1+r/100); } printf("%.2lf %d/n", p, cnt); return 0;}

-FIN-


发表评论 共有条评论
用户名: 密码:
验证码: 匿名发表