题目链接:https://leetcode.com/PRoblems/flatten-nested-list-iterator/?tab=Description
Given a nested list of integers, implement an iterator to flatten it.
Each element is either an integer, or a list -- whose elements may also be integers or other lists.
Example 1:Given the list [[1,1],2,[1,1]]
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By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,1,2,1,1]
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Example 2:Given the list [1,[4,[6]]]
,
By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,4,6]
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/** * // This is the interface that allows for creating nested lists. * // You should not implement it, or speculate about its implementation * class NestedInteger { * public: * // Return true if this NestedInteger holds a single integer, rather than a nested list. * bool isInteger() const; * * // Return the single integer that this NestedInteger holds, if it holds a single integer * // The result is undefined if this NestedInteger holds a nested list * int getInteger() const; * * // Return the nested list that this NestedInteger holds, if it holds a nested list * // The result is undefined if this NestedInteger holds a single integer * const vector<NestedInteger> &getList() const; * }; */class NestedIterator{public: NestedIterator(vector<NestedInteger> &nestedList) { vector<int> res; for(int i=0;i<nestedList.size();i++) flatten(nestedList[i]); k=0; } int next() { return flat[k++]; } bool hasNext() { return k<flat.size(); }private: vector<NestedInteger> vec; vector<int> flat; int k=0; void flatten(NestedInteger n) { if(n.isInteger()) { flat.push_back(n.getInteger()); return; } const vector<NestedInteger> v=n.getList(); for(int i=0;i<v.size();i++) flatten(v[i]); }};/** * Your NestedIterator object will be instantiated and called as such: * NestedIterator i(nestedList); * while (i.hasNext()) cout << i.next(); */
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