练习系统实验二 All in All

2019-11-06 08:23:29

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当前编程题：实验二进制转换问题(16级) ---All in All

问题描述You have devised a new encryption technique which encodes a message by inserting between its characters randomly generated strings in a clever way. Because of pending patent issues we will not discuss in detail how the strings are generated and inserted into the original message. To validate your method， however， it is necessary to write a PRogram that checks if the message is really encoded in the final string.Given two strings s and t， you have to decide whether s is a subsequence of t，i.e. if you can remove characters from t such that the concatenation of the remaining characters is s.输入形式The input contains several test cases. Each is specified by two strings s, t of alphanumeric ASCII characters separated by white space. The length of s and t will no more than 100000.输出形式For each test case output "Yes"， if s is a subsequence of t，otherwise output "No".样例输入4sequence subsequenceperson compressionVERDI vivaVittorioEmanueleReDiItaliacaseDoesMatter CaseDoesMatter样例输出YesNoYesNo说实话这个编的真是很顺哈哈

#include<stdio.h>#include<string.h>void handle(char aa[],char bb[]){int i,j,flag=0,k=0;for(i=0;i<strlen(aa);i++){for(j=k;j<strlen(bb);j++){if(aa[i]==bb[j]) { aa[i]='0'; bb[j]='1'; k=j; }}}for(i=0;i<strlen(aa);i++){if(aa[i]!='0'){flag=1;}}if(flag==1){printf("No/n");}else{printf("Yes/n");}}int main(){char aa[1000],bb[1000];int i,n;scanf("%d",&n);for(i=0;i<n;i++){scanf("%s%s",aa,bb);handle(aa,bb);}return 0;}