Jon Snow is on the lookout for some orbs required to defeat the white walkers. There are k different types of orbs and he needs at least one of each. One orb spawns daily at the base of a Weirwood tree north of the wall. The PRobability of this orb being of any kind is equal. As the north of wall is full of dangers, he wants to know the minimum number of days he should wait before sending a ranger to collect the orbs such that the probability of him getting at least one of each kind of orb is at least , where ε < 10 - 7.
To better prepare himself, he wants to know the answer for q different values of pi. Since he is busy designing the battle strategy with Sam, he asks you for your help.
InputFirst line consists of two space separated integers k, q (1 ≤ k, q ≤ 1000) — number of different kinds of orbs and number of queries respectively.
Each of the next q lines contain a single integer pi (1 ≤ pi ≤ 1000) — i-th query.
OutputOutput q lines. On i-th of them output single integer — answer for i-th query.
Examplesinput1 11output1input2 212output22http://codeforces.com/contest/768/problem/D
貌似是个概率dp,dp[i][j]表示已经过去i天,手里有j种不同颜色的气球的概率
#include<stdio.h>#include<algorithm>using namespace std;long double dp[10010][1010];int main(void){ int n, q, p, i, j; scanf("%d", &n); dp[0][0] = 1; for(i=0;i<=n*10;i++) { for(j=0;j<=min(i, n);j++) { dp[i+1][j] += dp[i][j]*j/n; dp[i+1][j+1] += dp[i][j]*(n-j)/n; } } scanf("%d", &q); while(q--) { scanf("%d", &p); for(i=n;dp[i][n]<p/2000.0;i++); printf("%d/n", i); } return 0;}
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