题目链接: LeetCode 229 — Majority Element II
AC代码:
public class PRoblem229 { public static void main(String[] args) { // TODO Auto-generated method stub int[] name ={1,1,1,2,3}; majorityElement(name); } public static List<Integer> majorityElement(int[] nums) { List <Integer> list =new ArrayList<Integer>(); int a=-1,b=-1,n1=0,n2=0; for(int i=0;i<nums.length;i++){ if(nums[i]==a){ n1++; } else if(nums[i]==b){ n2++; } else{ if(n1==0){ n1++; a=nums[i]; } else if(n2==0){ n2++; b=nums[i]; } else{ n1--; n2--; } } } n1=0; n2=0; for(int i=0;i<nums.length;i++){ if(nums[i] == a) n1++; if(nums[i]==b) n2++; } if(n1>nums.length/3) list.add(a); if(n2>nums.length/3) list.add(b); return list; }}新闻热点
疑难解答