Behind the scenes in the computer's memory, color is always talked about as a series of 24 bits of information for each pixel. In an image, the color with the largest PRoportional area is called the dominant color. A strictly dominant color takes more than half of the total area. Now given an image of resolution M by N (for example, 800x600), you are supposed to point out the strictly dominant color.
Input Specification:
Each input file contains one test case. For each case, the first line contains 2 positive numbers: M (<=800) and N (<=600) which are the resolutions of the image. Then N lines follow, each contains M digital colors in the range [0, 224). It is guaranteed that the strictly dominant color exists for each input image. All the numbers in a line are separated by a space.
Output Specification:
For each test case, simply print the dominant color in a line.
Sample Input:5 30 0 255 16777215 2424 24 0 0 2424 0 24 24 24Sample Output:24#include <cstdio>#include <iostream>#include <algorithm>#include <cstring>#include <string>#include <map>#define Max 51using namespace std;map<int ,int>S;int main(){ int n,m;int mm; scanf("%d%d",&n,&m); for(int i=0;i<n;i++) { for(int j=0;j<m;j++) { scanf("%d",&mm); if(S.find(mm)!=S.end()) S[mm]++; else S[mm]=1; } } int k; mm=0; for(map<int ,int >::iterator it = S.begin();it!=S.end();it++) { if(it->second>mm) { k=it->first; mm=it->second; } } printf("%d/n",k); system("pause"); return 0;}
新闻热点
疑难解答