1100.Mars Numbers (20)...to be continued...

2019-11-08 01:39:40

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1100.Mars Numbers (20)…to be continued…

pat-al-1100

2017-02-20

之前在乙级做过一遍，但是写的特别麻烦，这次参考书上优化了一下因为数的范围不大，选择使用map工具以及打表的方式atof：字符串转换成浮点数，在stdlib.h中c_str()：从string转成char数组/** * pat-al-1100 * 2017-02-20 * Cpp version * Author: fengLian_s */#include<stdio.h>#include<iostream>#include<stdlib.h>#include<map>#include<string>using namespace std;string unitDigit[13] = {"tret", "jan", "feb", "mar", "aPR", "may", "jun", "jly", "aug", "sep", "oct", "nov", "dec"};string tenDigit[13] = {"tret", "tam", "hel", "maa", "huh", "tou", "kes", "hei", "elo", "syy", "lok", "mer", "jou"};string num2Str[170];map<string, int> str2Num;void init(){ for(int i = 0;i < 13;i++) { num2Str[i] = unitDigit[i];//个位0~12，十位0 str2Num[unitDigit[i]] = i; num2Str[i*13] = tenDigit[i];//个位0，十位0~12 str2Num[tenDigit[i]] = i*13; } for(int i = 1;i < 13;i++)//十位 { for(int j = 1;j < 13;j++)//个位 { string str = tenDigit[i] + " " + unitDigit[j]; num2Str[i*13+j] = str; str2Num[str] = i*13+j; } }}int main(){ init(); freopen("in.txt", "r", stdin); int n; scanf("%d/n", &n); for(int i = 0;i < n;i++) { string str; getline(cin, str); //cout << "str = " << str << endl; if(str[0] >= '0' && str[0] <= '9') { int num = (int)atof(str.c_str()); cout << num2Str[num] << endl; } else cout << str2Num[str] << endl; } return 0;}

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