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LeetCode 66. Plus One

2019-11-08 02:02:18
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Given a non-negative integer rePResented as a non-empty array of digits, plus one to the integer.

You may assume the integer do not contain any leading zero, except the number 0 itself.

The digits are stored such that the most significant digit is at the head of the list.

程序代码:

/** * Return an array of size *returnSize. * Note: The returned array must be malloced, assume caller calls free(). */int* plusOne(int* digits, int digitsSize, int* returnSize) { int flag = 0,i,tmp; digits[digitsSize-1]++; for(i=digitsSize-1;i>=0;i--) { tmp = digits[i] + flag; digits[i] = tmp % 10; flag = tmp/10; } *returnSize = flag==1?digitsSize+1:digitsSize; int* res = (int*)malloc(*returnSize*sizeof(int)); if(flag) { res[0] = 1; for(i=0;i<digitsSize;i++) res[i+1] = digits[i]; } else { for(i=0;i<digitsSize;i++) res[i] = digits[i]; } return res; }
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