You are given two non-empty linked lists rePResenting two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
You may assume the two numbers do not contain any leading zero, except the number 0 itself. Examples:
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)Output: 7 -> 0 -> 8程序代码：
/** * Definition for singly-linked list. * struct ListNode { * int val; * struct ListNode *next; * }; */struct ListNode* addTwoNumbers(struct ListNode* l1, struct ListNode* l2) { struct ListNode *p,*q,*r,*m,*tmp; p=l1,q=l2; int sum=0,flag = 0; r = (struct ListNode*)malloc(sizeof(struct ListNode)); m=r; while(p!=NULL&&q!=NULL) { tmp = (struct ListNode*)malloc(sizeof(struct ListNode)); sum = p->val + q->val + flag; flag=sum>=10?1:0; tmp->val = sum%10; tmp->next = NULL; m->next = tmp; m= m->next; p=p->next; q=q->next; } while(p!=NULL) { tmp = (struct ListNode*)malloc(sizeof(struct ListNode)); sum = p->val + flag; flag=sum>=10?1:0; tmp->val = sum%10; tmp->next = NULL; m->next = tmp; m= m->next; p=p->next; } while(q!=NULL) { tmp = (struct ListNode*)malloc(sizeof(struct ListNode)); sum = q->val + flag; flag=sum>=10?1:0; tmp->val = sum%10; tmp->next = NULL; m->next = tmp; m= m->next; q=q->next; } if(flag) { tmp = (struct ListNode*)malloc(sizeof(struct ListNode)); tmp->val = 1; tmp->next = NULL; m->next = tmp; m=m->next; } return r->next;}新闻热点
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