Note: This is an extension of House Robber.
After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will not get too much attention. This time, all houses at this place are arranged in a circle. That means the first house is the neighbor of the last one. Meanwhile, the security system for these houses remain the same as for those in the PRevious street.
Given a list of non-negative integers representing the amount of money of each house, determine the maximum amount of money you can rob tonight without alerting the police.
public class Solution { public int rob(int[] nums) { if (nums == null || nums.length == 0) return 0; if (nums.length == 1) return nums[0]; return Math.max(helper(nums, 0, nums.length-2), helper(nums, 1, nums.length-1)); } public int helper(int[] nums, int low, int high) { int include = 0, exclude = 0; for (int i = low; i <= high; i++) { int in = include, ex = exclude; include = ex + nums[i]; exclude = Math.max(in, ex); } return Math.max(include, exclude); }}class Solution {public: int rob(vector<int>& nums) { if (nums.empty() || nums.size() == 0) return 0; if (nums.size() == 1) return nums[0]; return max(helper(nums, 0, nums.size()-2), helper(nums, 1, nums.size()-1)); } int helper(vector<int>& nums, int low, int high) { int include = 0, exclude = 0; for (int i = low; i <= high; i++) { int in = include, ex = exclude; include = ex + nums[i]; exclude = max(in, ex); } return max(include, exclude); }};新闻热点
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