华为OJ：学英语

2019-11-08 02:11:18

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题目描述 Jessi初学英语，为了快速读出一串数字，编写程序将数字转换成英文：如22：twenty two，123：one hundred and twenty three。

说明：数字为正整数，长度不超过九位，不考虑小数，转化结果为英文小写；输出格式为twenty two；非法数据请返回“error”；关键字提示：and，billion，million，thousand，hundred。

方法原型：public static String parse(long num)

输入描述: 输入一个long型整数

输出描述: 输出相应的英文写法

输入例子: 2356

输出例子: two thousand three hundred and fifty six

#include <iostream>#include <string>using namespace std;string s1[20] = {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine","ten","eleven","twelve", "thirteen", "fourteen","fifteen","sixteen","seventeen", "eighteen", "nineteen"};//string s2[10] = {"ten","eleven","twelve", "thirteen", "fourteen","fifteen","sixteen","seventeen", "eighteen", "nineteen"};string s3[10] ={"twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"};string lessThan100(long num){ string result; if(num < 20) result = s1[num-1]; else if (num <100 && num%10 == 0 ) result = s3[num/10-2]; else if (num <100) result = s3[num/10-2]+" "+s1[num%10-1]; return result;}string lessThan1000(long num){ string result; if(num < 100) result = lessThan100(num); else if(num%100 == 0) result = s1[num/100-1] + " hundred"; else result = (s1[num/100 -1]+" hundred and "+ lessThan100(num%100)); return result;}string lessThanMillion(long num){ string result; if(num < 1000) result = lessThan1000(num); else if(num % 1000 == 0) result = lessThan1000(num/1000) + " thousand"; else result = lessThan1000(num/1000) + " thousand "+ lessThan1000(num%1000); return result;}string lessThanBillion(long num){ string result; if(num <1000000) result = lessThanMillion(num); else if(num % 1000000 ==0) result = lessThanMillion(num/1000000) + " million"; else result = lessThanMillion(num/1000000) + " million " + lessThanMillion(num%1000000); return result;}string parse(long num) { string result; if(num <= 0 || num >=10000000000) result = "ERROR"; else if(num < 1000) result = lessThan1000(num); else if(num < 1000000) result = lessThanMillion(num); else if(num <1000000000) result = lessThanBillion(num); else if (num == 1000000000) result = "one billion"; else result = s1[num/1000000000-1]+" billion "+ lessThanBillion(num%1000000000); return result;}int main(){ /*cout << parse(30) << endl; cout << lessThan1000(15) << endl; cout << lessThan1000(36) << endl; cout << lessThan1000(100) << endl; cout << lessThan1000(909) << endl; cout << lessThan1000(999) << endl; cout << lessThanMillion(1000) << endl; cout << lessThanMillion(1009) << endl; cout << lessThanMillion(10009) << endl; cout << lessThanMillion(100009) << endl; cout << lessThanBillion(1000009) << endl; cout << lessThanBillion(1009009) << endl; cout << parse(1000000000) << endl; cout << parse(1000000009) << endl;*/ long num =0 ; cin >> num; cout << parse(num); return 0;}

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