LeetCode 40. Combination Sum II

Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.

Each number in C may only be used once in the combination.

Note:

For example, given candidate set [10, 1, 2, 7, 6, 1, 5] and target 8, A solution set is: 

[  [1, 7],  [1, 2, 5],  [2, 6],  [1, 1, 6]]
class Solution {public:	vector<vector<int>> combinationSum2(vector<int>& candidates, int target) {		sort(candidates.begin(),candidates.end());		vector<int> temp;		vector<vector<int>> result;		myComb2(candidates,target,0,temp,result);		return result;	}	void myComb2(vector<int>& candidates, int target,int index,vector<int> & temp,vector<vector<int>> & result){		//        		if(target < 0) return;		if(target == 0){			//            temp.push_back(candidates[index]);			result.push_back(temp);			return;		}				for(int i = index; i < candidates.size() && target >= candidates[i]; i ++){			if((i == index) || (candidates[i] != candidates[i - 1])){				temp.push_back(candidates[i]);				myComb2(candidates,target - candidates[i],i + 1,temp,result);				temp.pop_back();			}		}	}};