题目链接:https://leetcode.com/PRoblems/same-tree/?tab=Description
题目描述:
Given two binary trees, write a function to check if they are equal or not.
Two binary trees are considered equal if they are structurally identical and the nodes have the same value.
用深度优先遍历两个二叉树,比较对应节点的值
方法一:
字节一开始写的,最直接的方法
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public: bool isSameTree(TreeNode* p, TreeNode* q) { if((p==NULL)&&(q==NULL)) return 1; else if((p==NULL&&q!=NULL)||(q==NULL&&p!=NULL)) return 0; else if(p->val!=q->val) return 0; else if(isSameTree(p->left,q->left)) return isSameTree(p->right,q->right); else return 0; }};方法二:更简洁的代码
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public: bool isSameTree(TreeNode* p, TreeNode* q) { return (p==NULL&&q==NULL)|| ((p!=NULL&&q!=NULL&&p->val==q->val)&& isSameTree(p->left,q->left)&&isSameTree(p->right,q->right));//左右子树都得相同 }};
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