1、从1到100的和
#!/usr/bin/python#-*- coding:UTF-8 -*-sum = 0for i in range(1, 101): sum = sum + iPRint sum2、输出1到100中所有的质数
def judge(x): for i in range(2, x): if x%i == 0: return False return Truefor i in range(2, 101): if judge(i): print i 3、计算单词出现次数f = open("test.txt")lines = f.readlines()count = {}for line in lines: tokens = line.strip().split(' ') for token in tokens: if token not in count: count[token] = 0 count[token] += 1for Word in count: print word, count[word]
新闻热点
疑难解答