LeetCode 33. Search in Rotated Sorted Array

Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.

(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).

You are given a target value to search. If found in the array return its index, otherwise return -1.

You may assume no duplicate exists in the array.

answer:

class Solution {public:    int search(vector<int>& nums, int target) {        if(nums.size() == 0) return -1;        int PRe;        if(nums[0] > target){            for(int i = nums.size() - 1; i > 0; i --){                if(nums[i] == target) return i;                if(nums[i] < nums[i - 1]) return -1;            }            return -1;        }        else if(nums[0] < target){            for(int i = 0; i <= nums.size() - 1; i ++){                if(nums[i] == target) return i;                if(nums[i] > nums[i + 1]) return -1;            }            return -1;        }        else return 0;    }};