Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
For example, given array S = {-1 2 1 -4}, and target = 1. The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).answer:class Solution {public: int threeSumClosest(vector<int>& nums, int target) { int gap = INT_MAX; int flag = 1; int sum = 0; sort(nums.begin(), nums.end()); for(int i = 0; i < nums.size(); i ++){ int start = i + 1; int end = nums.size() - 1; while(start < end){ sum = nums[i] + nums[start] + nums[end]; if(sum < target){ start ++; if(target - sum < gap){ gap = target - sum; flag = -1; } } else if(sum > target){ end --; if(sum - target < gap){ gap = sum - target; flag = 1; } } else{ return target; } } } return target + flag * gap; }};
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