PAT BASIC 1014 福尔摩斯的约会

2019-11-11 01:19:32

字体：大中小

来源：转载

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思路：

一个判定条件比较复杂的字符串处理题，感觉又是题目表达得不太明确，没什么特别要注意的，条件之间的&&和||关系不要搞错就好了。

代码：

#include<iostream>#include<string>using namespace std;string a, b;int len, week, hour, minu;string eWeek[7] = { "MON ", "TUE ", "WED ", "THU ", "FRI ", "SAT ", "SUN " };int main(){ int i, j; cin >> a >> b; len = 0; while (!(a[len] == b[len] && a[len] >= 'A' && a[len] <= 'G')) len++; week = a[len] - 'A'; len++; while (!(a[len] == b[len] && ((a[len] >= 'A' && a[len] <= 'N') || (a[len] >= '0' && a[len] <= '9')))) len++; if (a[len] >= '0' && a[len] <= '9') hour = a[len] - '0'; else hour = a[len] - 'A' + 10; cin >> a >> b; len = 0; while (!(a[len] == b[len] && ((a[len] >= 'a' && a[len] <= 'z') || (a[len] >= 'A' && a[len] <= 'Z')))) len++; minu = len; cout << eWeek[week]; if (hour < 10) cout << "0"; cout << hour << ":"; if (minu < 10) cout << "0"; cout << minu; //while (1) //{ //} return 0;}

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