PHP遍历目录返回统计目录大小实例

分享一个 PHP遍历目录并返回统计目录大小的方法。代码：

<?php $dirname = "test1"; //mkdir($dirname);//遍历一层目录 function listdir($dirname) { $ds = opendir($dirname); while($file = readdir($ds)) { $path = $dirname.'/'.$file; if(is_dir($file)) { echo "DIR:".$file."<br>"; if($file != "." && $file != "..") { listdir($file); } } else { echo "FILE:".$file . "<br>"; } } }function totdir($dirname) { //对listdir稍加修改 static $tot = 0; $ds = opendir($dirname); while($file = readdir($ds)) { $path = $dirname.'/'.$file; if(is_dir($file)) { //echo "DIR:".$file."<br>"; if($file != "." && $file != "..") { $tot += totdir($file); } } www.jbxue.comelse { //echo "FILE:".$file . "<br>"; $tot += filesize($path); } }//返回总计 return $tot; }listdir($dirname);echo totdir($dirname)." bytes";?>