JS判断数组里是否有重复元素的方法小结

var ary11 = new Array("1", "ff", "11", "aa", "2222");// 验证重复元素，有重复返回true；否则返回falsefunction mm(a) {  return /(/x0f[^/x0f]+)/x0f[/s/S]*/1/.test("/x0f" + a.join("/x0f/x0f") + "/x0f");}mm(ary11)alert(mm(ary11))

var ary = ["1", "ff", "11", "aa", "2222"]var s = ary.join(",") + ",";for(var i = 0; i < ary.length; i++) {  if(s.replace(ary[i] + ",", "").indexOf(ary[i] + ",") > -1) {    alert("数组中有重复元素：" + ary[i]);    break;  }}

var ary = new Array("11", "222", "33", "111", "22");var nary = ary.sort();for(var i = 0; i < nary.length - 1; i++) {  if(nary[i] == nary[i + 1]) {    alert("重复内容：" + nary[i]);  }}

var ary = new Array("1111", "222", "33", "111", "22");alert(isRepeat(ary));// 验证重复元素，有重复返回true；否则返回falsefunction isRepeat(arr) {  var hash = {};  for(var i in arr) {    if(hash[arr[i]]) {      return true;    }    // 不存在该元素，则赋值为true，可以赋任意值，相应的修改if判断条件即可    hash[arr[i]] = true;  }  return false;}