php查询操作实现投票功能

2019-11-21 22:09:06

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本文实例为大家分享了php查询操作实现投票功能的代码，供大家参考，具体内容如下

题目：

解题方法汇总：

方法一：
1. 投票主页面：

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head><meta http-equiv="Content-Type" content="text/html; charset=utf-8" /><title>投票</title><style>#list{  width:400px;  height:300px;}#jieguo{  width:400px;  height:300px;}.x{     float:left;} </style></head> <body> <form action="TouChuLi.php" method="post"><?phpinclude ("DBDA.class.php");$db=new DBDA();//从调研题目表中找出题目代号和名称$sql="select * from diaoyantimu limit 0,1";$arr=$db->query($sql);$tmmc=$arr[0][1];$tmdh=$arr[0][0];echo "<div><h2>{$tmmc}:</h2></div>";//从调研选项表中输出选项内容：$sqlxx="select * from diaoyanxuanxiang where timudaihao='{$tmdh}'";$arrxx=$db->query($sqlxx);echo "<div id='list'>";foreach ($arrxx as $v){  echo "<div><input type='checkbox' value='{$v[0]}' name='xx[]'>{$v[1]}</div><br />";} ?><input type="submit" value="提交"><input type="button" value="查看结果" id="check" onclick="Showjieguo()"></form></div> <div id="jieguo" style="display:none"><?php//计算总人数：$sqlzs="select sum(numbers) from diaoyanxuanxiang where timudaihao='{$tmdh}'";$zrs=$db->query($sqlzs); foreach ($arrxx as $v){     $name=$v[1];  $number=$v[2];  if($zrs[0][0]==0)   {     $bfb = 0;   }   else   {     $bfb = ($number/$zrs[0][0])*100;   }  $bfb=round($bfb,2);  echo "<div>    <span class='x'>{$name} </span>    <div class='x' style='width:200px; height:10px; background-color:#808080'>    <div style='width:{$bfb}%; height:10px; background-color:#FF8040'> </div>    </div>    <span class='x'>{$number} </span>    <span class='x'>{$bfb}% </span>    </div>    <br />    "; }?><input type="button" value="返回" id="fanhui" onclick="Showfanhui()"></div><script>function Showjieguo(){  document.getElementById("list").style.display="none";  document.getElementById("jieguo").style.display="block";  }function Showfanhui(){  document.getElementById("list").style.display="block";  document.getElementById("jieguo").style.display="none";  }</script> </body></html>

2.处理投票页面：

<?php$arr=$_POST["xx"];include ("../DBDA.class.php");$db=new DBDA();  foreach($arr as $v){  $sql = "update diaoyanxuanxiang set numbers = numbers+1 where ids = '{$v}'";  $db->Query($sql,1);//1代表$sql的类型}header ("location:TouPiao.php");?>

3.　建立访问数据库的类,封装用于引用：

<?php//执行一个sql语句，返回相应的结果class DBDA{  public $host="localhost";//数据库服务器地址  public $uid="root";//数据库用户名  public $password="";//数据库密码  //执行SQL语句的方法  //参数里面：$sql代表要执行的sql语句；$type是sql语句的类型，0代表查询，1代表其他(增删改)；$db代表要操作的数据库  function Query($sql,$type=0,$db="mydb")  {    //造连接对象    $dbconnect=new MySQLi($this->host,$this->uid,$this->password,$db);    //判断连接是否出错    !mysqli_connect_error() or die("连接失败！");    //执行sql语句    $result=$dbconnect->query($sql);    //判断SQL语句类型    if($type==0)    {       //如果是查询语句返回结果集的二维数组      return $result->fetch_all();      }    else    {      //如果是其他语句，返回true或false      return $result;      }       }       }

方法二：

1. 投票主页面：

<html><head><meta http-equiv="Content-Type" content="text/html; charset=utf-8" /><title>投票</title><style>.x{     float:left;} </style></head> <body> <form action="TouChuLi.php" method="post"><?phpinclude ("../DBDA.class.php");$db=new DBDA();//从调研题目表中找出题目代号和名称$sql="select * from diaoyantimu limit 0,1";$arr=$db->query($sql);$tmmc=$arr[0][1];$tmdh=$arr[0][0];echo "<div><h2>{$tmmc}:</h2></div>";//从调研选项表中输出选项内容：$sqlxx="select * from diaoyanxuanxiang where timudaihao='{$tmdh}'";$arrxx=$db->query($sqlxx);echo "<div id='list'>";foreach ($arrxx as $v){  echo "<div><input type='checkbox' value='{$v[0]}' name='xx[]'>{$v[1]}</div><br />";} ?><input type="submit" value="提交"><a href="ChaKan.php"><input type="button" value="查看结果" id="check" ></a></form></body></html>

2. 处理投票页面：

<?php$arr=$_POST["xx"];include ("../DBDA.class.php");$db=new DBDA();  foreach($arr as $v){  $sql = "update diaoyanxuanxiang set numbers = numbers+1 where ids = '{$v}'";  $db->Query($sql,1);//1代表$sql的类型}header ("location:TouPiao.php");?>

3. 查看投票结果页面：

<html><head><meta http-equiv="Content-Type" content="text/html; charset=utf-8" /><title>查看结果</title><style>.x{  float:left;}</style></head><body> <?phpinclude ("../DBDA.class.php");$db=new DBDA();//从调研题目表中找出题目代号和名称$sql="select * from diaoyantimu limit 0,1";$arr=$db->query($sql);$tmmc=$arr[0][1];echo "<div><h2>{$tmmc}:</h2></div>";//从调研选项表中输出选项内容：$sqlxx="select * from diaoyanxuanxiang where timudaihao='{$arr[0][0]}'";$arrxx=$db->query($sqlxx); //计算总人数：$sqlzs="select sum(numbers) from diaoyanxuanxiang where timudaihao='{$arr[0][0]}'";$zrs=$db->query($sqlzs); foreach ($arrxx as $v){   $name=$v[1];//调研项目名称   $number=$v[2];//选择该项的人数   //判断总人数是否为0   if($zrs[0][0]==0)   {     $bfb = 0;   }   else   {     $bfb = ($number/$zrs[0][0])*100;//求百分比   }     $bfb=round($bfb,2); //取小数点后两位  echo "<div>  <span class='x'>{$name} </span>  <div class='x' style='width:200px; height:10px; background-color:#808080'>  <div style='width:{$bfb}%; height:10px; background-color:#FF8040'> </div>  </div>  <span class='x'>{$number} </span>  <span class='x'>{$bfb}%</span><br />  </div><br />"; }?><br /><a href="TouPiao.php"><input type="button" value="返回"></a></body></html>

显示结果：