linux进程监控shell脚本代码

为确保php页面在后台运行，写了一个监控脚本，假设程序异常退出，那么可以自动重启。

shell脚本/usr/local/scripts/receve.sh内容：

#!/bin/bash#funtion:keep receve.php runningPHP="/usr/local/php5/bin/php"PROGRAM="receve.php"#start dameo$PHP /home/httpd/$PROGRAM >>/usr/local/scripts/phpshell/receve.out &chpid="$!";echo "$chpid" > /usr/local/scripts/phpshell/receve.sidecho "child pid is $chpid"echo "status is $?"while [ 1 ]dowait $chpidexitstatus="$?"echo "child pid=$chpid is gone, $exitstatus" >>/usr/local/scripts/phpshell/receve.php_error.logecho `date` >> /usr/local/scripts/phpshell/receve.php_error.logecho "**************************" >>/usr/local/scripts/phpshell/receve.php_error.logsleep 10$PHP /home/httpd/$PROGRAM >> /usr/local/scripts/phpshell/receve.out &chpid="$!";echo "$chpid" > /usr/local/scripts/phpshell/receve.sidecho "next child pid is $chpid"echo "next status is $?"done

需要保证监控脚本正常运行，在每天凌晨自动重启脚本/usr/local/scripts/restart_r.sh，写入crontab：

#!/bin/bashecho "" >/tmp/receve_pid.txt/bin/ps ax | /bin/grep "receve.sh" | /bin/grep -v "grep" | /bin/awk '{print $1}' >/tmp/receve_pid.txtno1pid=`cat /tmp/receve_pid.txt | sort -r`no2pid=`cat /usr/local/scripts/phpshell/receve.sid | sort -r`if [ -z $no1pid ];then  echo "receve.sh pid is null, receve.sh is not running." else    /bin/kill -9 "$no1pid"    echo "receve.sh killed"fisleep 3if [ -z $no2pid ];then  echo "receve.php pid is null, receve.php is not running." else  /bin/kill -9 "$no2pid"  echo "receve.php killed"firm -rf /usr/local/scripts/phpshell/receve.sid sleep 3 /usr/local/scripts/receve.sh > /dev/null &

crontab：

代码如下:
#restart receve.sh
10 00 * * * /usr/local/scripts/restart_r.sh

注意：脚本命名要避免重复，避免自己kill掉自己的进程。