492. Construct the Rectangle

For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

1. The area of the rectangular web page you designed must equal to the given target area.2. The width W should not be larger than the length L, which means L >= W.3. The difference between length L and width W should be as small as possible.You need to output the length L and the width W of the web page you designed in sequence.
Example:
Input: 4Output: [2, 2]Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. But according to requirement 2, [1,4] is illegal; according to requirement 3,  [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.
Note:
The given area won't exceed 10,000,000 and is a positive integerThe web page's width and length you designed must be positive integers.
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所求最小偏差的m,l值，所以从area开平方根的地方开始向两边扩展来算。
public int[] constructRectangle(int area) {       int[] re={0,0};	   int result= (int) Math.sqrt(area);       if(result*result==area){    	   re[0]=re[1]=result;       }else {    	   for (int i = result; i < area+1; i++) {    		   int m=area/i;    		   if(m*i==area){    			   if (m>i) {    				   re[0]=m;re[1]=i;    			   }else {					re[0]=i;re[1]=m;    			   }    			   break;    		   }		}		}       return re;    }