开发android中，解决View.getLocationOnScreen为0

今天在使用PopWindow.showAtLocation(View parent, int gravity, int x, int y)时，最后2个参数的传值问题，1.首先使用了View.getLocationOnScreen(new Location[]) 或者 getLocationInWindow(new Location[]);获取到的location[0]及location[1]有时为02.使用View.getGlobalVisibleRect(new Rect());获取rect.left view距屏幕左边的间距，rect.top view距屏幕上边的间距；获取到的值不为0；

最终解决：

int p1 = Util.dip2px(168);int[] location = new int[2];parent.getLocationInWindow(location);int l1 = location[0];int l2 = location[1];if (l1 == 0 || l2 == 0) {    Rect rect = new Rect();    parent.getGlobalVisibleRect(rect);    l1 = rect.left;    l2 = rect.top;}pop.showAtLocation(parent, Gravity.NO_GRAVITY, l1 - p1, l2);