Java判断回文串

2019-11-11 03:25:33

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import java.nio.file.DirectoryStream.Filter;

import javax.swing.JOptionPane;

public class PalindromeIgnoreNonAlphanumeric {

public static void main(String[] args) { // TODO Auto-generated method stub String s=JOptionPane.showInputDialog("Enter a string:"); String output="Ignoring nonalphanumeric characters,/nis" +s+"a palindrome?" +isPalindrome(s); JOptionPane.showMessageDialog(null, output);}//判读是否是回文串public static boolean isPalindrome(String s){ String s1=filter(s);//去除非字母和数字 String s2=reverse(s1);//字符串反转 return s2.equals(s1);}public static String filter(String s){ StringBuffer strBuf=new StringBuffer(); for(int i=0;i<s.length();i++) { if(Character.isLetterOrDigit(s.charAt(i))){ strBuf.append(s.charAt(i)); } } return strBuf.toString();}public static String reverse(String s){ StringBuffer stringBuffer=new StringBuffer(s); stringBuffer.reverse(); return stringBuffer.toString();}

}

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