首页 > 学院 > 开发设计 > 正文

体验游戏编程网站

2019-11-14 17:47:08
字体:
来源:转载
供稿:网友

最近学习python,想要找点练习,在看《python核心编程》(真是一本好书,非常详细,觉得看这一本书就够了,余下可以翻翻文档)。觉得cf之类的虽然能用python提交但是重点不是在学习python上 。终于找到了两个不错的网站checkio和pythonchallenge。今天先看看了看checkio确实很适合练习语法。

加载的速度有点慢,进去点两下就可以开始敲题了,题目还有提示

第一个题是清除列表中只出现了一次的元素:

 1 #Your optional code here 2 #You can import some modules or create additional functions 3  4  5 def checkio(data): 6     #Your code here 7     #It's main function. Don't remove this function 8     #It's used for auto-testing and must return a result for check.   9 10     l=len(data)11     temp=[]12     i=013     for i in range(l):14         if data.count(data[i])>1:15             temp.append(data[i])16     data=temp;17     return data18 19 #Some hints20 #You can use list.count(element) method for counting.21 #Create new list with non-unique elements22 #or remove elements from original list (but it's bad PRactice for many real cases)23 #Loop over original list24 25 26 if __name__ == "__main__":27     #These "asserts" using only for self-checking and not necessary for auto-testing28     assert isinstance(checkio([1]), list), "The result must be a list"29     assert checkio([1, 2, 3, 1, 3]) == [1, 3, 1, 3], "1st example"30     assert checkio([1, 2, 3, 4, 5]) == [], "2nd example"31     assert checkio([5, 5, 5, 5, 5]) == [5, 5, 5, 5, 5], "3rd example"32     assert checkio([10, 9, 10, 10, 9, 8]) == [10, 9, 10, 10, 9], "4th example"
View Code

当然根据提示敲个这个出来就足以说明我的新手程度了,在这里你还可以看到很多的非常好的解法,比如:

 1 #Your optional code here 2 #You can import some modules or create additional functions 3   4   5 def checkio(data): 6         return [i for i in data if data.count(i) > 1] 7   8 #Some hints 9 #You can use list.count(element) method for counting.10 #Create new list with non-unique elements11 #or remove elements from original list (but it's bad practice for many real cases)12 #Loop over original list13  14  15 #These "asserts" using only for self-checking and not necessary for auto-testing16 if __name__ == "__main__":17     assert isinstance(checkio([1]), list), "The result must be a list"18     assert checkio([1, 2, 3, 1, 3]) == [1, 3, 1, 3], "1st example"19     assert checkio([1, 2, 3, 4, 5]) == [], "2nd example"20     assert checkio([5, 5, 5, 5, 5]) == [5, 5, 5, 5, 5], "3rd example"21     assert checkio([10, 9, 10, 10, 9, 8]) == [10, 9, 10, 10, 9], "4th example"
View Code

当然这里我的主要目的是学习语言,就暂且不最球效率什么的了

其实后面的就没提示了。。。。

第二题,求中位数

 1 def checkio(data): 2  3     data.sort() 4     l=len(data) 5     if l%2==0: 6         data[0]=(data[l/2-1]+data[l/2])/2.0 7     else: 8         data[0]=data[l/2]  9     return data[0]10 11 #These "asserts" using only for self-checking and not necessary for auto-testing12 if __name__ == '__main__':13     assert checkio([1, 2, 3, 4, 5]) == 3, "Sorted list"14     assert checkio([3, 1, 2, 5, 3]) == 3, "Not sorted list"15     assert checkio([1, 300, 2, 200, 1]) == 2, "It's not an average"16     assert checkio([3, 6, 20, 99, 10, 15]) == 12.5, "Even length"17     print("Start the long test")18     assert checkio(range(1000000)) == 499999.5, "Long."19     print("The local tests are done.")
View Code

另外这有个很有意思的解法,利用了负的索引,写的非常好,语言特性mark!

 1 def checkio(data): 2     off = len(data) // 2 3     data.sort() 4     med = data[off] + data[-(off + 1)] 5     return med / 2 6  7 #These "asserts" using only for self-checking and not necessary for auto-testing 8 if __name__ == '__main__': 9     assert checkio([1, 2, 3, 4, 5]) == 3, "Sorted list"10     assert checkio([3, 1, 2, 5, 3]) == 3, "Not sorted list"11     assert checkio([1, 300, 2, 200, 1]) == 2, "It's not an average"12     assert checkio([3, 6, 20, 99, 10, 15]) == 12.5, "Even length"
View Code

 判断密码的强度,其实也就是判断是否存在某些值

 1 def checkio(data): 2  3     #replace this for solution 4      5     l=len(data) 6     digist=False 7     upp=False 8     low=False 9     if l<10:10         return False11     for i in data:12         if i<='9' and i>='0':13             digist=True14         elif i<='z' and i>='a':15             low=True16         elif i<='Z' and i>='A':17             upp=True18     if digist and upp and low:19         return True20     else:21         return False22 23 #Some hints24 #Just check all conditions25 26 27 if __name__ == '__main__':28     #These "asserts" using only for self-checking and not necessary for auto-testing29     assert checkio(u'A1213pokl') == False, "1st example"30     assert checkio(u'bAse730onE4') == True, "2nd example"31     assert checkio(u'asasasasasasasaas') == False, "3rd example"32     assert checkio(u'QWERTYqwerty') == False, "4th example"33     assert checkio(u'123456123456') == False, "5th example"34     assert checkio(u'QwErTy911poQQqq') == True, "6th example"
View Code

其实还可以用一些函数的但是感觉挺难记,还不如自己写呢

持续更新。。。


发表评论 共有条评论
用户名: 密码:
验证码: 匿名发表