最近学习python,想要找点练习,在看《python核心编程》(真是一本好书,非常详细,觉得看这一本书就够了,余下可以翻翻文档)。觉得cf之类的虽然能用python提交但是重点不是在学习python上 。终于找到了两个不错的网站checkio和pythonchallenge。今天先看看了看checkio确实很适合练习语法。
加载的速度有点慢,进去点两下就可以开始敲题了,题目还有提示
第一个题是清除列表中只出现了一次的元素:
1 #Your optional code here 2 #You can import some modules or create additional functions 3 4 5 def checkio(data): 6 #Your code here 7 #It's main function. Don't remove this function 8 #It's used for auto-testing and must return a result for check. 9 10 l=len(data)11 temp=[]12 i=013 for i in range(l):14 if data.count(data[i])>1:15 temp.append(data[i])16 data=temp;17 return data18 19 #Some hints20 #You can use list.count(element) method for counting.21 #Create new list with non-unique elements22 #or remove elements from original list (but it's bad PRactice for many real cases)23 #Loop over original list24 25 26 if __name__ == "__main__":27 #These "asserts" using only for self-checking and not necessary for auto-testing28 assert isinstance(checkio([1]), list), "The result must be a list"29 assert checkio([1, 2, 3, 1, 3]) == [1, 3, 1, 3], "1st example"30 assert checkio([1, 2, 3, 4, 5]) == [], "2nd example"31 assert checkio([5, 5, 5, 5, 5]) == [5, 5, 5, 5, 5], "3rd example"32 assert checkio([10, 9, 10, 10, 9, 8]) == [10, 9, 10, 10, 9], "4th example"
当然根据提示敲个这个出来就足以说明我的新手程度了,在这里你还可以看到很多的非常好的解法,比如:
1 #Your optional code here 2 #You can import some modules or create additional functions 3 4 5 def checkio(data): 6 return [i for i in data if data.count(i) > 1] 7 8 #Some hints 9 #You can use list.count(element) method for counting.10 #Create new list with non-unique elements11 #or remove elements from original list (but it's bad practice for many real cases)12 #Loop over original list13 14 15 #These "asserts" using only for self-checking and not necessary for auto-testing16 if __name__ == "__main__":17 assert isinstance(checkio([1]), list), "The result must be a list"18 assert checkio([1, 2, 3, 1, 3]) == [1, 3, 1, 3], "1st example"19 assert checkio([1, 2, 3, 4, 5]) == [], "2nd example"20 assert checkio([5, 5, 5, 5, 5]) == [5, 5, 5, 5, 5], "3rd example"21 assert checkio([10, 9, 10, 10, 9, 8]) == [10, 9, 10, 10, 9], "4th example"
当然这里我的主要目的是学习语言,就暂且不最球效率什么的了
其实后面的就没提示了。。。。
第二题,求中位数
1 def checkio(data): 2 3 data.sort() 4 l=len(data) 5 if l%2==0: 6 data[0]=(data[l/2-1]+data[l/2])/2.0 7 else: 8 data[0]=data[l/2] 9 return data[0]10 11 #These "asserts" using only for self-checking and not necessary for auto-testing12 if __name__ == '__main__':13 assert checkio([1, 2, 3, 4, 5]) == 3, "Sorted list"14 assert checkio([3, 1, 2, 5, 3]) == 3, "Not sorted list"15 assert checkio([1, 300, 2, 200, 1]) == 2, "It's not an average"16 assert checkio([3, 6, 20, 99, 10, 15]) == 12.5, "Even length"17 print("Start the long test")18 assert checkio(range(1000000)) == 499999.5, "Long."19 print("The local tests are done.")
另外这有个很有意思的解法,利用了负的索引,写的非常好,语言特性mark!
1 def checkio(data): 2 off = len(data) // 2 3 data.sort() 4 med = data[off] + data[-(off + 1)] 5 return med / 2 6 7 #These "asserts" using only for self-checking and not necessary for auto-testing 8 if __name__ == '__main__': 9 assert checkio([1, 2, 3, 4, 5]) == 3, "Sorted list"10 assert checkio([3, 1, 2, 5, 3]) == 3, "Not sorted list"11 assert checkio([1, 300, 2, 200, 1]) == 2, "It's not an average"12 assert checkio([3, 6, 20, 99, 10, 15]) == 12.5, "Even length"
判断密码的强度,其实也就是判断是否存在某些值
1 def checkio(data): 2 3 #replace this for solution 4 5 l=len(data) 6 digist=False 7 upp=False 8 low=False 9 if l<10:10 return False11 for i in data:12 if i<='9' and i>='0':13 digist=True14 elif i<='z' and i>='a':15 low=True16 elif i<='Z' and i>='A':17 upp=True18 if digist and upp and low:19 return True20 else:21 return False22 23 #Some hints24 #Just check all conditions25 26 27 if __name__ == '__main__':28 #These "asserts" using only for self-checking and not necessary for auto-testing29 assert checkio(u'A1213pokl') == False, "1st example"30 assert checkio(u'bAse730onE4') == True, "2nd example"31 assert checkio(u'asasasasasasasaas') == False, "3rd example"32 assert checkio(u'QWERTYqwerty') == False, "4th example"33 assert checkio(u'123456123456') == False, "5th example"34 assert checkio(u'QwErTy911poQQqq') == True, "6th example"
其实还可以用一些函数的但是感觉挺难记,还不如自己写呢
持续更新。。。
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