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webwork入门文章

2019-11-18 11:23:37
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 (1) 在tomcat/webapp/中建立一个context(上下文)(tomcat/webapp/webwork);
     将webwork中的webwork_2.1.5.jar和/lib/core中的所有.jar文件
    加入到tomcat/webapp/webwork/web-info/lib中;

(2) 修改web.xml如下:

<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
    version="2.4">
<servlet>
  <servlet-name>webwork</servlet-name>
  <servlet-class>com.opensymphony.webwork.dispatcher.ServletDispatcher</servlet-class>
  <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
  <servlet-name>webwork</servlet-name>
  <url-pattern>*.action</url-pattern>
</servlet-mapping>
<taglib>
  <taglib-uri>webwork</taglib-uri>
  <taglib-location>/WEB-INF/lib/webwork-2.1.5.jar</taglib-location>
</taglib>
</web-app>

(3)在webwork/classes中加入xwork.xml配置文件:

<!DOCTYPE xwork PUBLIC "-//OpenSymphony Group//XWork 1.0//EN"
"http://www.opensymphony.com/xwork/xwork-1.0.dtd"><xwork>
 <!-- Include webwork defaults (from WebWork-2.1 JAR). -->
 <include file="webwork-default.xml" />
 <!-- Configuration for the default package. -->
 <package name="default" extends="webwork-default">
   <!-- Default interceptor stack. -->
    <default-interceptor-ref name="defaultStack" />
      <action name="hello" class="org.HelloAction">
      <result name="error" type="dispatcher">index.jsp</result>
      <result name="sUCcess" type="dispatcher">success.jsp</result>
    </action>
</package>
</xwork>
(4)创建HelloAction.java文件(HelloAction 类是用来处理请求的):
package org;

import com.opensymphony.xwork.ActionSupport;

public class HelloAction extends ActionSupport {
  String person;
  public String getPerson() {
    return person;
  }
  public void setPerson(String person) {
    this.person = person;
  }
  public String execute() throws Exception {


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