python超时重新请求解决方案

# -*- coding: utf-8 -*-import randomimport time import eventletfrom retrying import retry eventlet.monkey_patch()  class RetryTimeOutException(Exception):  def __init__(self, *args, **kwargs):    pass  def retry_if_timeout(exception):  """Return True if we should retry (in this case when it's an IOError), False otherwise"""  return isinstance(exception, RetryTimeOutException)  def retry_fun(retries=3, timeout_second=2):  """  will retry ${retries} times when process time beyond ${timeout_second} ;  :param retries: The retry times  :param timeout_second: The max process time  """   def retry_decor(func):    @retry(stop_max_attempt_number=retries, retry_on_exception=retry_if_timeout)    def decor(*args, **kwargs):      print("In retry method..")      pass_flag = False      with eventlet.Timeout(timeout_second, False):        r = func(*args, **kwargs)        pass_flag = True        print("Success after method.")      if not pass_flag:        raise RetryTimeOutException("Time out..")      print("Exit from retry.")      return r     return decor   return retry_decor  def do_request():  print("begin request...")  sleep_time = random.randint(1, 4)  print("request sleep time: %s." % sleep_time)  time.sleep(sleep_time)  print("end request...")  return True  @retry_fun(retries=3)def retry_request():  r = do_request()  print(r)  if __name__ == '__main__':  retry_request()