使用 ProcessPoolExecutor
from concurrent.futures import ProcessPoolExecutor, as_completedimport random
斐波那契数列
当 n 大于 30 时抛出异常
def fib(n): if n > 30: raise Exception('can not > 30, now %s' % n) if n <= 2: return 1 return fib(n-1) + fib(n-2)准备数组
nums = [random.randint(0, 33) for _ in range(0, 10)]'''[13, 17, 0, 22, 19, 33, 7, 12, 8, 16]'''
方案一：submit
submit 输出结果按照子进程执行结束的先后顺序，不可控
with ProcessPoolExecutor(max_workers=3) as executor: futures = {executor.submit(fib, n):n for n in nums} for f in as_completed(futures): try: print('fib(%s) result is %s.' % (futures[f], f.result())) except Exception as e: print(e)'''fib(13) result is 233.fib(17) result is 1597.fib(0) result is 1.fib(22) result is 17711.fib(19) result is 4181.can not > 30, now 33fib(7) result is 13.fib(12) result is 144.fib(8) result is 21.fib(16) result is 987.'''等价写法：
with ProcessPoolExecutor(max_workers=3) as executor: futures = {} for n in nums: job = executor.submit(fib, n) futures[job] = n for job in as_completed(futures): try: re = job.result() n = futures[job] print('fib(%s) result is %s.' % (n, re)) except Exception as e: print(e)'''fib(13) result is 233.fib(17) result is 1597.fib(0) result is 1.fib(22) result is 17711.can not > 30, now 33fib(7) result is 13.fib(19) result is 4181.fib(8) result is 21.fib(12) result is 144.fib(16) result is 987.'''方案二：map
map 输出结果按照输入数组的顺序
缺点：某一子进程异常会导致整体中断
with ProcessPoolExecutor(max_workers=3) as executor: try: results = executor.map(fib, nums) for num, result in zip(nums, results): print('fib(%s) result is %s.' % (num, result)) except Exception as e: print(e)'''fib(13) result is 233.fib(17) result is 1597.fib(0) result is 1.fib(22) result is 17711.fib(19) result is 4181.can not > 30, now 33'''以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持武林网。
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