Python切图九宫格的实现方法

# -*- coding: utf-8 -*-'''将一张图片填充为正方形后切为9张图'''from PIL import Imageimport sys#将图片填充为正方形def fill_image(image):  width, height = image.size  #选取长和宽中较大值作为新图片的  new_image_length = width if width > height else height  #生成新图片[白底]  new_image = Image.new(image.mode, (new_image_length, new_image_length), color='white')  #将之前的图粘贴在新图上，居中  if width > height:#原图宽大于高，则填充图片的竖直维度    #(x,y)二元组表示粘贴上图相对下图的起始位置    new_image.paste(image, (0, int((new_image_length - height) / 2)))  else:    new_image.paste(image, (int((new_image_length - width) / 2),0))  return new_image#切图def cut_image(image):  width, height = image.size  item_width = int(width / 3)  box_list = []  # (left, upper, right, lower)  for i in range(0,3):#两重循环，生成9张图片基于原图的位置    for j in range(0,3):      #print((i*item_width,j*item_width,(i+1)*item_width,(j+1)*item_width))      box = (j*item_width,i*item_width,(j+1)*item_width,(i+1)*item_width)      box_list.append(box)  image_list = [image.crop(box) for box in box_list]  return image_list#保存def save_images(image_list):  index = 1  for image in image_list:    image.save('./python'+str(index) + '.png', 'PNG')    index += 1if __name__ == '__main__':  file_path = "python.jpeg"  image = Image.open(file_path)  #image.show()  image = fill_image(image)  image_list = cut_image(image)  save_images(image_list)