详解python路径拼接os.path.join()函数的用法

2019-11-25 11:37:03

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os.path.join()函数：连接两个或更多的路径名组件

1.如果各组件名首字母不包含'/'，则函数会自动加上

demo1

import osPath1 = 'home'Path2 = 'develop'Path3 = 'code'Path10 = Path1 + Path2 + Path3Path20 = os.path.join(Path1,Path2,Path3)print ('Path10 = ',Path10)print ('Path20 = ',Path20)

输出：

Path10 = homedevelopcode
Path20 = home/develop/code

2.如果有一个组件是一个绝对路径，则在它之前的所有组件均会被舍弃

demo2

import os Path1 = '/home'Path2 = 'develop'Path3 = 'code'Path10 = Path1 + Path2 + Path3Path20 = os.path.join(Path1, Path2, Path3)Path30 = os.path.join(Path2, Path1, Path3)print('Path10 = ',Path10)print('Path20 = ',Path20)print('Path30 = ',Path30)

　输出：

Path10 = /homedevelopcode
Path20 = /home/develop/code
Path30 = /home/code

3.如果最后一个组件为空，则生成的路径以一个'/'分隔符结尾

demo3

import osPath1 = 'home'Path2 = 'develop'Path3 = ''Path10 = Path1 + Path2 + Path3Path20 = os.path.join(Path1, Path2, Path3)Path30 = os.path.join(Path2, Path1, Path3)print('Path10 = ',Path10)print('Path20 = ',Path20)

输出：