首页 > 编程 > Python > 正文

利用Python检测URL状态

2019-11-25 12:09:09
字体:
来源:转载
供稿:网友

需求:Python检测URL状态,并追加保存200的URL

代码一:

#! /usr/bin/env python#coding=utf-8import sysimport requestsdef getHttpStatusCode(url):  try:    request = requests.get(url)    httpStatusCode = request.status_code    return httpStatusCode  except requests.exceptions.HTTPError as e:    return e if __name__ == "__main__":  with open('1.txt', 'r') as f:    for line in f:      try:        status = getHttpStatusCode(line.strip('/n'))#换行符        if status == 200:          with open('200.txt','a') as f:            f.write(line + '/n')            print line        else:          print 'no 200 code'      except Exception as e:        print e

代码二:

#! /usr/bin/env python# -*--coding:utf-8*-import requestsdef request_status(line):  conn = requests.get(line)  if conn.status_code == 200:    with open('url_200.txt', 'a') as f:      f.write(line + '/n')    return line13   else:    return Noneif __name__ == '__main__':  with open('/1.txt', 'rb') as f:    for line in f:      try:        purge_url = request_status(line.strip('/n'))      except Exception as e:        pass

代码三:

#! /usr/bin/env python#coding:utf-8import os,urllib,linecacheimport sysresult = list()for x in linecache.updatecache(r'1.txt'):  try:    a = urllib.urlopen(x.replace('/n','')).getcode()    #print x,a  except Exception,e:    print e  if a == 200:    #result.append(x)               #保存    #result.sort()                    #排序结果    #open('2.txt', 'w').write('%s' % '/n'.join(result)) #保存入结果文件    with open ('200urllib.txt','a') as f: ## r只读,w可写,a追加      f.write(x + '/n')  else:    print 'error'

总结

以上所述是小编给大家介绍的python 检测url 状态,希望对大家有所帮助,如果大家有任何疑问请给我留言,小编会及时回复大家的。在此也非常感谢大家对武林网网站的支持!
如果你觉得本文对你有帮助,欢迎转载,烦请注明出处,谢谢!

发表评论 共有条评论
用户名: 密码:
验证码: 匿名发表