用python3 返回鼠标位置的实现方法(带界面)

#!/usr/bin/python3# -*- coding: UTF-8 -*-import timeimport pyautogui as pagimport tkinterdef get():  po.delete(0,tkinter.END)	time.sleep(2) #几秒后返回位置  x , y = pag.position()  po.insert(0,str(x)+','+str(y))root = tkinter.Tk()tip = tkinter.Label(root,text="返回点击获取2s后的光标位置")tip.grid(row=0)po = tkinter.Entry(root)po.grid(row=1)do = tkinter.Button(root,text="获取",command=get) #点击获取位置do.grid(row=2)root.mainloop()

#!/usr/bin/python3# -*- coding: UTF-8 -*-import timeimport pyautogui as pagimport tkintermytime = 2#判断时间是否合法def safe():				text = getmytime.get();	#小数点个数	point = 0	if(text==""):		return False	for i in text:		if(i>='0' and i<='9'and point<2):			continue		elif(i=='.'):			point = point + 1		else:			return False	return Truedef get():	global mytime	if(safe()):		mytime = float(getmytime.get())				#不知道为何下面的这个if没用		if(mytime>7.0):			showpos.delete(0,tkinter.END)			showpos.insert(0,"请耐心等候")			time.sleep(mytime) #几秒后返回位置		x , y = pag.position()		showpos.delete(0,tkinter.END)		showpos.insert(0,str(x)+','+str(y))	else:		showpos.delete(0,tkinter.END)		showpos.insert(0,"输入非法哟~") root = tkinter.Tk()root.resizable(0,0)tip1 = tkinter.Label(root,text="点击按钮获取")tip1.place(relx=0.1,rely=0.1)getmytime = tkinter.Entry(root,width=3)getmytime.place(relx=0.6,rely=0.1)getmytime.insert(0,str(mytime))tip2 = tkinter.Label(root,text="s后的")tip2.place(relx=0.8,rely=0.1)tip3 = tkinter.Label(root,text="光标位置:")tip3.place(relx=0.1,rely=0.3)showpos = tkinter.Entry(root,width=10)showpos.place(relx=0.5,rely=0.3)do = tkinter.Button(root,text="按钮",command=get) #点击获取位置do.place(relx=0.8,rely=0.6)root.mainloop()