python暴力解压rar加密文件过程详解

import itertools as itsimport stringdef createDict(path,repeats,words):	dict = its.product(words,repeat=repeats) 	'''这里的words是要迭代的字符串，repeats是生成的密码长度，生成的dict是一个返回元组的迭代器'''	f = open(path,'a')	for cipher in dict:		f.write(''.join(cipher) + '/n')	f.close()def main():	numbers = string.digits #包含0-9的字符串	path = '输入你的字典路径'	length = 你要迭代的密码长度	for i in range(1,length):		createDict(path,i,numbers)if __name__=="__main__":	main()

from threading import Threadfrom unrar import rarfileimport os'''首先我们要读取字典，字典可能太大因此我们采用迭代器'''def get_pwd(dict_path):	with open(dict_path,'r') as f:		for pwd in f:			yield pwd.strip()def decode_rar(fp,pwd,extract_path):	try:		fp.extractall(extract_path,pwd=pwd) 	except:		pass	else:		print('the pwd is>',pwd)'''事实上我在尝试时似乎从来没有到达过else，这样可能是得不到解压密码的。我的一种得到密码的想法如下，但是运行效率可能会降低def decode_rar(fp,pwd,check_file,extract_path):	fp.extractall(extract_path,pwd=pwd)	if os.path.exists(check_file):		print('The pwd is:',pwd)		exit(0)其中check_file可以设置为fp.namelist()[0]并且该方法不能使用多线程，因此速度会降低很多'''def main():	extract_path = '你要解压的路径'	dict_path = '你的字典路径'	filename = '你的rar路径'	fp = rarfile.RarFile(filename)	pwds = get_pwd(dict)	'''使用多线程可提高速度'''	for pwd in pwds:		t = Thread(target=rar_file,args=(fp,pwd,extract_path))		t.start()

import tkinter as tkimport osfrom tkinter import messageboxfrom unrar import rarfilefrom threading import Threaddef getPwd(dict):  with open(dict,'r') as f:    for pwd in f:      yield pwd.strip()def slowerDecode(fp,pwd,check_file,extract_path):  fp.extractall(extract_path,pwd=pwd)  if os.path.exists(check_file):    messagebox.showinfo(message="密码："+pwd)    messagebox.showinfo(message="程序结束")    messagebox.showinfo(message="密码："+pwd)    exit(0)	def quickDecode(fp,pwd,extract_path):  fp.extractall(extract_path,pwd=pwd)def check(obs):  flag = 1  for ob in obs:    if not ob.checkExist():      flag = 0      ob.showError()    if(not flag):    return 0  else:    for ob in obs:      if not ob.check():        flag = 0        ob.showError()		  if (not flag):    return 0  else:    for ob in obs:      ob.right()    return 1		def main(obs):  extract_path = obs[0].path_input.get()  rar_path = obs[1].path_input.get()  txt_path = obs[2].path_input.get()  pwds = getPwd(txt_path)  global var1  global var2  if(check(obs)):    if(var1.get() == 0 and var2.get() == 0):      messagebox.showerror(message="选择一个选项！！！")    elif(var1.get() == 0 and var2.get() == 1):      fp = rarfile.RarFile(rar_path)      check_file = fp.namelist()[0]      for pwd in pwds:        slowerDecode(fp,pwd,check_file,extract_path)    elif(var1.get() == 1 and var2.get() == 0):      fp = rarfile.RarFile(rar_path)      for pwd in pwds:        t = Thread(target=quickDecode,args=(fp,pwd,extract_path))        t.start()      exit(0)    else:      messagebox.showerror(message="只选择一个！！！")    class FolderPath:    def __init__(self,y=0,error_message="Not exists!",path_input="",text=''):    self.y = y    self.error_message = error_message    self.path_input = path_input    self.text = text	  def createLabel(self):    label = tk.Label(window,bg="white",font=("楷体",13),width=20,text=self.text)    cv.create_window(100,self.y,window=label)    def createEntry(self):  	entry = tk.Entry(window,fg="blue",width="40",bg="#ffe1ff",textvariable=self.path_input)  	cv.create_window(330,self.y,window=entry)    def show(self):    self.createLabel()    self.createEntry()	  def showError(self,color="red"):    label = tk.Label(window,bg="white",fg=color,font=("楷体",13),width="10",text=self.error_message)    cv.create_window(530,self.y,window=label)    def checkExist(self):    self.error_message = 'Not exists!'    if not os.path.exists(self.path_input.get()):      return 0    return 1    def check(self):    if not os.path.isdir(self.path_input.get()):      self.error_message = 'Not a dir!'      return 0    else:      return 1    def right(self):    self.error_message = "right path!"    self.showError('#00FFFF')	  class FilePath(FolderPath):  def check(self):    if (self.path_input.get().split('.')[-1] == self.suffix):      return 1    else:      self.error_message = "Not "+self.suffix + '!'      return 0  window = tk.Tk()window.title('made by qiufeng')window.geometry('600x300')cv = tk.Canvas(window,width=600,height=300,bg='white')cv.pack()folderpath = FolderPath(y=140,path_input=tk.StringVar(),text="请输入解压路径")folderpath.show()rarpath = FilePath(y=60,path_input=tk.StringVar(),text="请输入rar路径")rarpath.suffix = 'rar'rarpath.show()txtpath = FilePath(y=100,path_input=tk.StringVar(),text="请输入字典路径")txtpath.suffix = 'txt'txtpath.show()obs = [folderpath,rarpath,txtpath]#多选框var1 = tk.IntVar()var2 = tk.IntVar()ck1 = tk.Checkbutton(window,text="直接破解(无法获得密码)",variable=var1)cv.create_window(150,200,window=ck1)ck2 = tk.Checkbutton(window,text="慢速(可获得密码)",variable=var2)cv.create_window(132,230,window=ck2)button = tk.Button(window,text="确认",command=lambda: main(obs))cv.create_window(90,260,window=button)window.mainloop()