首页 > 编程 > Python > 正文

Python Tkinter 简单登录界面的实现

2019-11-25 12:45:30
字体:
来源:转载
供稿:网友

如下所示:

from tkinter import * class Reg (Frame):  def __init__(self,master):    frame = Frame(master)    frame.pack()    self.lab1 = Label(frame,text = "账户:")    self.lab1.grid(row = 0,column = 0,sticky = W)    self.ent1 = Entry(frame)    self.ent1.grid(row = 0,column = 1,sticky = W)    self.lab2 = Label(frame,text = "密码:")    self.lab2.grid(row = 1,column = 0)    self.ent2 = Entry(frame,show = "*")    self.ent2.grid(row = 1,column = 1,sticky = W)    self.button = Button(frame,text = "登录",command = self.Submit)    self.button.grid(row = 2,column = 1,sticky = E)    self.lab3 = Label(frame,text = "")    self.lab3.grid(row = 3,column = 0,sticky = W)    self.button2 = Button(frame,text = "退出",command = frame.quit)    self.button2.grid(row = 3,column = 3,sticky = E)  def Submit(self):    s1 = self.ent1.get()    s2 = self.ent2.get()    if s1 == 'admin' and s2 == '123':      self.lab3["text"] = "登陆成功"    else:      self.lab3["text"] = "用户名或密码错误!"    self.ent1.delete(0,len(s1))    self.ent2.delete(0,len(s2))root = Tk()root.title("用户登录")app = Reg(root)root.mainloop()

以上这篇Python Tkinter 简单登录界面的实现就是小编分享给大家的全部内容了,希望能给大家一个参考,也希望大家多多支持武林网。

发表评论 共有条评论
用户名: 密码:
验证码: 匿名发表