Python判断telnet通不通的实例

#!/usr/bin/env python# coding: utf8 import telnetlibimport timeimport codecsimport os # telnet hostdef telnetdo(host, statusFile): status1 = 'telnet success' status2 = 'telnet faild' for ipAdd in host: # get now time nowTime = time.strftime('%Y-%m-%d %H:%M:%S',time.localtime(time.time())) try:  t = telnetlib.Telnet(ipAdd, port=23, timeout=1)  writeToText(nowTime, ipAdd, status1, statusFile) except:  writeToText(nowTime, ipAdd, status2, statusFile)   # write status information to txtdef writeToText(nowTime, ipAdd, status, statusFile): s_text = 'TIME:' + nowTime + '/t' + 'IP:' + ipAdd + '/t' + 'STATUS:' + status + '/r/n'  if '0' == judgeFile(statusFile): with open(statusFile, 'a') as f:  f.write(s_text)  f.close()  if '1' == judgeFile(statusFile): with open(statusFile, 'w') as f:  f.write(s_text)  f.close()     # Determine whether statusFile exists # 0: exists# 1: no existsdef judgeFile(statusFile): if os.path.exists(statusFile): return '0' else: return '1'  if __name__ == "__main__": host = ['192.168.1.254', '192.168.1.100'] # write file statusFile = '/root/telnetStatus.txt' i = 7200 while i: telnetdo(host, statusFile) time.sleep(2) i = i - 1