python 获取url中的参数列表实例

import urlparseurldata = "http://en.wikipedia.org/w/api.php?action=query&ctitle=FA"result = urlparse.urlparse(urldata)print resultprint urlparse.parse_qs(result.query)

ParseResult(scheme='http', netloc='en.wikipedia.org', path='/w/api.php', params='', query='action=query&ctitle=FA', fragment=''){'action': ['query'], 'ctitle': ['FA']}