java计算集合对称差的示例代码

    <dependency>      <groupId>com.google.guava</groupId>      <artifactId>guava</artifactId>      <version>22.0</version>    </dependency>    <dependency>      <groupId>org.apache.commons</groupId>      <artifactId>commons-collections4</artifactId>      <version>4.1</version>    </dependency>

    Set<Integer> a = new HashSet<>(Arrays.asList(1, 2, 3, 4));    Set<Integer> b = new HashSet<>(Arrays.asList(3, 4, 5, 6));    Sets.SetView<Integer> result = Sets.symmetricDifference(a,b);    System.out.println(result);

    Set<Integer> a = new HashSet<>(Arrays.asList(1, 2, 5));    Set<Integer> b = new HashSet<>(Arrays.asList(1, 2, 3));    SetUtils.SetView<Integer> result = SetUtils.disjunction(a, b);    assertTrue(result.toSet().contains(5) && result.toSet().contains(3));

public static <O> Pair<Collection<O>,Collection<O>> disjunction2(final Collection<? extends O> first,                                  final Collection<? extends O> second,                                  final Predicate<O> p) {    final List<O> firstList = first.stream()        .filter(e -> p.evaluate(e))        .collect(Collectors.toList());    final List<O> secondList = second.stream()        .filter(e -> !firstList.remove(e))        .collect(Collectors.toList());    return Pair.of(firstList,secondList);  }

final List<String> first = Arrays.asList("bbb", "ccc","dddd","aaa");final List<String> second = Arrays.asList("aaa", "zzz", "ccc");System.out.println(disjunction(first,second,TruePredicate.truePredicate()));