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java异步方式实现登录

2019-11-26 14:18:27
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本文实例为大家分享了java异步登录的具体代码,供大家参考,具体内容如下

1.LoginServletAjax.java  

package com.scce.servlet; import java.io.IOException;import java.io.PrintWriter; import javax.servlet.ServletException;import javax.servlet.http.HttpServlet;import javax.servlet.http.HttpServletRequest;import javax.servlet.http.HttpServletResponse; import net.sf.json.JSONObject; import com.scce.dao.AdminUserDao;import com.scce.pojo.AdminUser; public class LoginServletAjax extends HttpServlet {   @Override  protected void service(HttpServletRequest request,      HttpServletResponse response) throws ServletException, IOException {    // TODO Auto-generated method stub    request.setCharacterEncoding("utf-8");    response.setContentType("text/html;charset=utf-8");    String method = request.getMethod();    if (method.equals("POST")) {      doLoginAjax(request, response);    } else if (method.equals("GET")) {     }   }   public void doLoginAjax(HttpServletRequest request,      HttpServletResponse response) throws ServletException, IOException {     PrintWriter out = response.getWriter();       // 用户名    String username = request.getParameter("username");    // 密码    String password = request.getParameter("password");       String msg = "";    AdminUserDao adminUserDao = new AdminUserDao();    AdminUser adminUser = adminUserDao.queryUser(username, password);    if (adminUser != null) {               msg="登录成功!";      String jsonObj=   JSONObject.fromObject(adminUser).toString();      out.print("{/"Msg/":/""+msg+"/",/"rows/":"+jsonObj+"}");      System.out.println("{/"Msg/":/""+msg+"/",/"rows/":"+jsonObj+"}");         } else {      msg="用户名或者密码不正确!";      out.print("{/"Msg/":/""+msg+"/"}");    }              out.flush();    out.close();   } }

2.test2.html

<!DOCTYPE html><html>  <head>    <title>chapter3-test2</title>     <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">    <meta http-equiv="description" content="this is my page">    <meta http-equiv="content-type" content="text/html; charset=UTF-8">       <link rel="stylesheet" href="../UI/themes/icon.css" type="text/css"></link>     <link rel="stylesheet" href="../UI/themes/default/easyui.css"      type="text/css"></link>     <!-- <script type="text/javascript" src="../js/jquery-1.8.2.min.js"></script> -->    <script type="text/javascript" src="../UI/jquery.min.js"></script>    <script type="text/javascript" src="../UI/jquery.easyui.min.js"></script>     <script type="text/javascript" src="../UI/locale/easyui-lang-zh_CN.js"></script>     <script type="text/javascript">  //string number boolean null object undefined function   $(function() {    $("#LoginAdd").dialog({      title : "用户登录",      collapsible : 'true',      width : 300,      height : 200,      buttons : [ {        text : '登录',        iconCls : 'icon-add',        handler : function() {          console.info("用户登录!");          ajaxFrm();//ajax提交表单的函数        }      } ]    });   });  function ajaxFrm() {    //------------------------注释的是ajax提交方法----------------------------    var LoginList = $("#LoginList");         $.ajax({      url : '../LoginServletAjax?tag=test',//相对路径访问      type : 'POST', //提交请求的方式      data : $('#form1').serialize()+'&names=liuqin&age=26',//将表单参数序列化,发送到服务器的数据(提交额外的参数)      dataType : 'json', //预期服务器返回的数据类型-json object        success : function(data) {//请求成功后将调用此方法var data = {"Msg":"登录成功","rows":{"username":"admin",...}}        console.info(data);//调试代码        $.messager.alert("提示", data.Msg);        LoginList.html("");//清空数据        if (data.rows) {          var stra = LoginList.html() + "用户名:" + data.rows.username              + "--密码:" + data.rows.password + "<br/>";          LoginList.html(stra);        }      },      error : function(error) { //请求失败时将调用此方法        console.info(error);       }    });      /*var LoginList = $("#LoginList");     $("#form1").form("submit", {       url: "../LoginServletAjax?tag=test",       onSubmit: function (param) { //提交额外的参数         param.name="liuqin";       param.age=27;         var username = $("#username").val();         var password = $("#password").val();         if (username.length == 0 || password.length == 0) {           $.messager.alert('警告', '请输入用户名和密码');           return false;         }         return true;       },       success: function (data) {          //var data = eval('(' + data + ')');          var data = $.parseJSON(data);//服务器端返回json字符串转成json对象-js object         console.info(data);         $.messager.alert("提示", data.Msg);         LoginList.html("");//清空数据          if (data.rows) {            var stra = LoginList.html() + "用户名:" + data.rows.username                + "--密码:" + data.rows.password + "<br/>";            LoginList.html(stra);          }       }     });*/   }</script>  </head>   <body>      <div id="LoginAdd">      <form id="form1" method="post">        <table style="width: 100%;">          <tr>            <td>              用户名:            </td>            <td>              <input id="username" name="username"                class="easyui-validatebox textbox">            </td>          </tr>          <tr>            <td>              密码:            </td>            <td>              <input id="password" name="password"                class="easyui-validatebox textbox" type="password">            </td>          </tr>        </table>      </form>    </div>    <div id="LoginList">      用户信息加载中......    </div>     <video width="320" height="240" controls="controls"      src="../video/B4934A0C53FC55703BFE3F6843E66166.mp4" type="video/mp4">      Your browser does not support the video tag.    </video>    </body></html>

以上就是本文的全部内容,希望对大家学习java程序设计有所帮助。

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