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C++类继承 继承后函数的值实现详解

2020-01-26 13:24:12
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类的继承会首先寻找基类,若基类未实现,则会寻找派生类的函数

1. class继承,函数不继承

#include <stdio.h> class Base{public:  Base(){}  ~Base(){}   int a;  void setA()  {    a = 1;  }}; class A:public Base{public:  A(){}  ~A(){}     void setA()  {    a = 2;  }   }; class B:public Base{public:  B(){}  ~B(){}     void setA()  {    a = 3;  }}; int main(){  A *ax = new A();  B *bx = new B();  Base *aClass = ax;  Base *bClass = bx;  aClass->setA();  bClass->setA();   printf("a value of a %d/n", aClass->a);  printf("a value of b %d/n", bClass->a);  return 0;}

运行结果:

2. 函数和Class都继承

#include <stdio.h> class Base{public:  Base(){}  ~Base(){}   int a;  virtual void setA()  {    a = 1;  }}; class A:public Base{public:  A(){}  ~A(){}     virtual void setA()  {    a = 2;  }   }; class B:public Base{public:  B(){}  ~B(){}     virtual void setA()  {    a = 3;  }}; int main(){  A *ax = new A();  B *bx = new B();  Base *aClass = ax;  Base *bClass = bx;  aClass->setA();  bClass->setA();   printf("a value of a %d/n", aClass->a);  printf("a value of b %d/n", bClass->a);  return 0;}

运行结果:注意派生类中可以不写virtual,最好写上,以辨别是函数继承

若将2中基类的函数写为纯虚函数,运行的结果一样,但是如果基类是纯虚函数,派生类必须实现相应的函数。

class Base{public:  Base(){}  ~Base(){}   int a;  virtual void setA()=0;   };

3. 类A中不有函数,则继承自基类

class A:public Base{public:  A(){}  ~A(){}   };

结果为:

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