代码很简单,这里就不多废话了,直接奉上:
#include <iostream>using namespace std; int* reverse(int* list, int size){ for (int i = 0, j = size - 1; i < j; i++, j--) {  // Swap list[i] with list[j]  int temp = list[j];  list[j] = list[i];  list[i] = temp; }  return list;} void printArray(int* const list, int size){ for (int i = 0; i < size; i++)  cout << list[i] << " ";} int main(){ int list[] = {1, 2, 3, 4, 5, 6}; int* p = reverse(list, 6); printArray(p, 6);  return 0;}另附上一则网友的写法
#include<math.h>int main(void){  char c[100][100];  int i=0,j;  char a;  while (1)  {    scanf("%s%c",c[i],&a);    if (a=='/n')    {      break;    }    i++;  }  for (j=i; j>=0; j--) {    printf("%s ",c[j]);  }  return 0;}新闻热点
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