这篇文章主要介绍了C语言实现的程序员老黄历,涉及日期的判定及流程控制的相关技巧,具有一定参考借鉴价值,需要的朋友可以参考下
本文实例讲述了C语言实现的程序员老黄历。分享给大家供大家参考。具体如下:
以前看到过一个jquery程序员老黄历页面,觉得挺有创意的,自己闲着用C语言也写了一个,基本就是随机数的生成,没什么难度,大家随便看看,高手请绕过此篇,控制台程序没什么美观可言,已经尽量弄得好看点了。
- #include <stdio.h>
- #include <time.h>
- int random(int dayseed,int indexseed)
- //根据当前时间“天 ”产生伪随机数。
- {
- int i,n;
- n = dayseed % 11117;
- for (i = 0; i < 100 + indexseed; i++)
- {
- n = n * n;
- n = n % 11117; // 11117 是个质数
- }
- return n;
- }
- int isWeekend(struct tm *p)
- {
- return p->tm_wday == 0 || p->tm_wday == 6;
- }
- int main(int argc, char *argv[])
- {
- char *weeks[6] = {"一","二","三","四","五","六","日"};
- printf("|-------------------------------------|/n");
- printf("| 程序员老黄历beta 1.0 |/n");
- printf("|-------------------------------------|/n");
- time_t timep;
- struct tm *p;
- time(&timep);
- p =localtime(&timep);
- //此函数获得的tm结构体的时间,是已经进行过时区转化为本地时间
- printf("|-------------------------------------|/n");
- printf("| 今天是%d年%d月%d日 星期%s |/n",1900+p->tm_year,1+p->tm_mon,p->tm_mday,weeks[p->tm_wday-1]);
- printf("|-------------------------------------|/n");
- int randNum=random(p->tm_mday, 2);//产生伪随机数
- int randNum1=random(p->tm_mday, 3);
- char *activities[27][3] = {
- {"写单元测试", "写单元测试将减少出错","写单元测试会降低你的开发效率"},
- {"白天上线", "今天白天上线是安全的","可能导致灾难性后果"},
- {"重构", "代码质量得到提高","你很有可能会陷入泥潭"},
- {"使用%t", "你看起来更有品位","别人会觉得你在装逼"},
- {"跳槽", "该放手时就放手","鉴于当前的经济形势,你的下一份工作未必比现在强"},
- {"招人", "你遇到千里马的可能性大大增加","你只会招到一两个混饭吃的外行"},
- {"面试", "面试官今天心情很好","面试官不爽,会拿你出气"},
- {"提交辞职申请", "公司找到了一个比你更能干更便宜的家伙,巴不得你赶快滚蛋","鉴于当前的经济形势,你的下一份工作未必比现在强"},
- {"申请加薪", "老板今天心情很好","公司正在考虑裁员"},
- {"晚上加班", "晚上是程序员精神最好的时候","", },
- {"命名变量/"%v/"", "",""},
- {"写超过%l行的方法", "你的代码组织的很好,长一点没关系","你的代码将混乱不堪,你自己都看不懂"},
- {"提交代码", "遇到冲突的几率是最低的","你遇到的一大堆冲突会让你觉得自己是不是时间穿越了"},
- {"代码复审", "发现重要问题的几率大大增加","你什么问题都发现不了,白白浪费时间"},
- {"开会", "写代码之余放松一下打个盹,有益健康","你会被扣屎盆子背黑锅"},
- {"晚上上线", "晚上是程序员精神最好的时候","你白天已经筋疲力尽了"},
- {"修复BUG", "你今天对BUG的嗅觉大大提高","新产生的BUG将比修复的更多"},
- {"设计评审", "设计评审会议将变成头脑风暴","人人筋疲力尽,评审就这么过了"},
- {"需求评审", "",""},
- {"打DOTA", "你将有如神助","你会被虐的很惨", }, //这里往下的是周末特定情况 (19-27)
- {"洗澡", "你几天没洗澡了?","会把设计方面的灵感洗掉", },
- {"锻炼一下身体", "","能量没消耗多少,吃得却更多", },
- {"抽烟", "抽烟有利于提神,增加思维敏捷","除非你活够了,死得早点没关系", },
- {"在妹子面前吹牛", "改善你矮穷挫的形象","会被识破", },
- {"撸管", "避免缓冲区溢出","强撸灰飞烟灭", },
- {"浏览成人网站", "重拾对生活的信心","你会心神不宁", },
- {"上微博", "今天发生的事不能错过","会看到令人心情不好的事", },
- {"上AB站", "还需要理由吗?","满屏的兄贵我会说出来?", }
- };
- printf("|-------------------------------------|/n");
- if(isWeekend(p))
- printf("| 宜: /n| %2s/n| %s/n",activities[19+randNum%8][0],activities[randNum%27][1]);
- else
- printf("| 宜: /n| %2s/n| %s/n",activities[randNum%17][0],activities[randNum%27][1]);
- printf("|-------------------------------------|/n");
- printf("|-------------------------------------|/n");
- if(isWeekend(p))
- printf("| 不宜:/n| %s/n| %s/n",activities[19+randNum1%8][0],activities[randNum1%27][2]);
- else
- printf("| 不宜:/n| %s/n| %s/n",activities[randNum1%17][0],activities[randNum1%27][2]);
- printf("|-------------------------------------|/n");
- /*座位朝向*/
- char *directions[8]= {"北方","东北方","东方","东南方","南方","西南方","西方","西北方"};
- printf("|-------------------------------------|/n");
- printf("| 座位朝向:面向 %s 写程序,BUG 最少./n",directions[randNum%8]);
- /*今日宜饮*/
- char *drinks[14] = {"水","茶","红茶","绿茶","咖啡","奶茶","可乐","牛奶","豆奶","果汁","果味汽水","苏打水","运动饮料","酸奶","酒"};
- printf("|-------------------------------------|/n");
- printf("| 今日宜饮:%s,%s/n",drinks[randNum%14],drinks[randNum1%14]);
- /*女神亲近指数*/
- int ambiguous = randNum%10;
- printf("|-------------------------------------|/n");
- if(10==ambiguous)
- printf("| 亲近指数为10,上吧,骚年!/n");
- else
- printf("| 女神亲近指数:%d /n",ambiguous);
- printf("|-------------------------------------|/n");
- return 0;
- }
运行效果如下图所示:
希望本文所述对大家的C语言程序设计有所帮助。
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